(3x^2+2x+1)*(2x-3)=

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Solution for (3x^2+2x+1)*(2x-3)= equation: 


Simplifying
(3x2 + 2x + 1)(2x + -3) = 0

Reorder the terms:
(1 + 2x + 3x2)(2x + -3) = 0

Reorder the terms:
(1 + 2x + 3x2)(-3 + 2x) = 0

Multiply (1 + 2x + 3x2) * (-3 + 2x)
(1(-3 + 2x) + 2x * (-3 + 2x) + 3x2 * (-3 + 2x)) = 0
((-3 * 1 + 2x * 1) + 2x * (-3 + 2x) + 3x2 * (-3 + 2x)) = 0
((-3 + 2x) + 2x * (-3 + 2x) + 3x2 * (-3 + 2x)) = 0
(-3 + 2x + (-3 * 2x + 2x * 2x) + 3x2 * (-3 + 2x)) = 0
(-3 + 2x + (-6x + 4x2) + 3x2 * (-3 + 2x)) = 0
(-3 + 2x + -6x + 4x2 + (-3 * 3x2 + 2x * 3x2)) = 0
(-3 + 2x + -6x + 4x2 + (-9x2 + 6x3)) = 0

Combine like terms: 2x + -6x = -4x
(-3 + -4x + 4x2 + -9x2 + 6x3) = 0

Combine like terms: 4x2 + -9x2 = -5x2
(-3 + -4x + -5x2 + 6x3) = 0

Solving
-3 + -4x + -5x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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